What is the equation of the line that is parallel to y = negative two-thirds x + 4 and that passes through (–2,–2)?

On a coordinate plane, a line goes through (3, 2), and (6, 0). A point is at (negative 2, negative 2).
y = negative two-thirds x minus four-thirds
y = negative two-thirds x minus StartFraction 10 Over 3 EndFraction
y = negative two-thirds x minus two-thirds
y = negative two-thirds x minus StartFraction 17 Over 4 EndFraction

the answer is. -82562234434584

step-by-step explanation:

c. side angle side. u shares the same sides

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).