An object is thrown upward from the top of a building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation When will the object hit the ground?

5 secs

Step-by-step explanation:

The height of the object is given as:

The moment when the object hits the ground, the height of the object will be 0 m.

Hence:

Solving this for t:

Divide through by 16 and move all parameters to the left hand side:

Since time cannot be negative, time, t = 5 secs.

The object will hit the ground after 5 secs.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)