Random sample found that forty percent of 100 Americans were satisfied with the gun control laws in 2017. Compute a 99% confidence interval for the true proportion of Americans who were satisfied with the gun control laws in 2017.

The 99% confidence interval for the true proportion of Americans who were satisfied with the gun control laws in 2017 is (0.274, 0.526).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

For this problem, we have that:

99% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the true proportion of Americans who were satisfied with the gun control laws in 2017 is (0.274, 0.526).

the answer for this question is 38