Two friends are making lemonade to sell at their lemonade stand. First, they make 2 gallons of lemonade containing 30% lemon juice, but that doesn't taste quite right to them. They decide to add some store-bought lemonade that is 20% lemon juice until they have a mixture that is 23% lemon juice. How much of the store-bought lemonade should they add

They should add gallons of the store-bought lemonade.

Step-by-step explanation:

Given that,

Two friends make 2 gallons of lemonade containing 30% lemon juice.

The amount of lemon juice in 2 gallons of lemonade is

= 30% of 2 gallons

gallons

Let they added x gallons of store-bought lemonade that contains 20% lemon juice.

The amount of  lemon juice in x gallons of lemonade is

= 20% of x gallons

gallons

Now the total amount of lemon juice in the mixture is

gallons

gallons

Total amount of lemonade is = (2+x) gallons.

The percentage of lemon juice in the lemonade is

According to the problem,

⇒ 60+20x= 23(2+x)

⇒60+20x= 46+23x

⇒23x-20x= 60-46

⇒3x=14

gallon

They should add gallons of the store-bought lemonade.

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72

step-by-step explanation: