Mathematics, 15.04.2020 02:00 ashhleyjohnson
A sample of n = 25 n=25 diners at a local restaurant had a mean lunch bill of $16 with a standard deviation of σ = $ 4 σ=$4 . We obtain a 95% confidence interval as ( 14.43 , 17.57 ) (14.43,17.57) . Which choice correctly interprets this interval? None of the answer options are correct. 95% of all lunches will cost between $14.43 and $17.57. 95% of the time, the average price for a lunch will be between $14.43 and $17.57. 95% of all samples of size n = 25 n=25 will have an average lunch price between $14.43 and $17.57.
Answers: 3
Mathematics, 21.06.2019 15:00
Simplify (a/b - b/a) times (a - a^2/a+b) a - a^2/a=b is a mixed number
Answers: 2
Mathematics, 21.06.2019 16:30
An airport in death valley is 60 feet below sea level, and an airplane is flying 2,000 feet above sea level. how many feet must the plane descend in order to land? a. 2060 b. 2000 feet c. 1940 feet d. 1880 feet e.1400 feet will mark as brainliest
Answers: 2
Mathematics, 21.06.2019 17:40
Multiply. write your answer in simplest form. 3/8 x 5/7
Answers: 1
Mathematics, 22.06.2019 02:00
The quotient of 15 and a number is 1 over 3 written as an equation
Answers: 1
A sample of n = 25 n=25 diners at a local restaurant had a mean lunch bill of $16 with a standard de...
Computers and Technology, 07.06.2020 02:02