Now my SIXTH time asking and I'm getting annoyed.
Beth is planning a playground and has d...
Mathematics, 15.04.2020 00:35 bellbug08
Now my SIXTH time asking and I'm getting annoyed.
Beth is planning a playground and has decided to place the swings in such a way that they are the same distance from the jungle gym and the monkey bars. If Beth places the swings at point D, how could she prove that point D is equidistant from the jungle gym and monkey bars?
If segment AD ≅ segment CD, then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent.
If segment AD ≅ segment CD, then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects.
If m∠ACD = 90° then point D is equidistant from points A and B because congruent parts of congruent triangles are congruent.
If m∠ACD = 90° then point D is equidistant from points A and B because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects.
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