A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 72 specimens and counts the number of seeds in each. Use her sample results (mean = 56.1, standard deviation = 16.7) to find the 99% confidence interval for the number of seeds for the species. Enter your answer as an open-interval (i. e., parentheses) accurate to one decimal place (because the sample statistics are reported accurate to one decimal place).

99% Confidence interval:   (50.9,61.3)        

Step-by-step explanation:

We are given the following in the question:

Sample mean, = 56.1

Sample size, n = 72

Alpha, α = 0.01

Sample standard deviation, σ = 16.7

Degree of freedom = n - 1 = 71

99% Confidence interval:  

Putting the values, we get,  

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.