A truck can be rented from Company A for $100100 a day plus $0.300.30 per mile. Company B charges $7070 a day plus $0.600.60 per mile to rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.

100 miles

Step-by-step explanation:

Hi to answer this question we have to write a system of equations.

To obtain the cost of company A (A) we have to add the fixed cost (100) and the product of the cost per mile (30) an the number of miles (d) .

A = 100+ 0.30d

Same for the cost of company B (B)

B= 70+ 0.60d

To find the number of miles in a day at which the rental costs for Company A and Company B are the same, both costs must be equal.

A =B

So

100+ 0.30d=70+ 0.60d

Solving for d

100-70 =0.60d-0.30d

30=0.30d

30/0.30=d

d= 100 miles

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

i dont know sorry

step-by-step explanation: