16. What is the (approximate) probability that Die1+Die2+Die3=6? a. Probability is approximately 5% b. Probability is approximately 10% c. Probability is approximately 20% d. Probability is approximately 25% 17. What is the (approximate) probability that Die1+Die2+Die3>12?

A.) Probability is approximately 5%

B.) probability that Die1 + Die + Die > 12 is approximately 26%

Step-by-step explanation:

Total possible outcomes of the three dies (sample space) = (6^3) = 216

For die1 + die2 + die3 to be equal six, then the number of outcomes which produces our required outcome from the sample space is = 6

Therefore, probability of die1 + die2 + die3 = 6 is given by;

P(die1 + die2 + die3 = 6) = total required outcome / total possible outcomes

P(die1 + die2 + die3 = 6) = 10/216

P( die1 + die2 + die3 = 6) = 0.04629

P( die1 + die2 + die3 = 6) = 4.63% approximately 5%

B) probability that Die1 + Die + Die > 12

P(Die1 + Die + Die > 12) = 57/216 = 0.2638

= 26.38%

Approximately 26%

damm bro the struggle

step-by-step explanation:

can you rephrase the question ? it is unclear : -)

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