A sample of 300 FM residents was taken and 135 said their favorite season was summer. Calculate a 99% confidence interval for the proportion of FM residents whose favorite season is summer. What is the lower bound of this interval? (Round your answer to 3 decimal places and enter it with a leading 0. ex: 0.XXX).

The 99% confidence interval for the proportion of FM residents whose favorite season is summer is between (0.376, 0.524).

The lower bound of this interval is 0.376.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

For this problem, we have that:

99% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the proportion of FM residents whose favorite season is summer is between (0.376, 0.524).

The lower bound of this interval is 0.376.

the correct answer is option c.   3

step-by-step explanation:

points to remember

equation of the line with coordinates (x₁, y₁) and (x₂, y₂) is given by,

slope m = (y₂ - y₁)/(x₂ - x₁)

from the figure we can see a line with two coordinates given

to find the slope of given line

here   (x₁, y₁)   = (-1, -1 ) and (x₂, y₂) = (1, 5)

slope m = (y₂ - y₁)/(x₂ - x₁)

  = (5 - -1)/(1 - -1)

  = (5 + 1)/(1 + 1)

  = 6/2 = 3

therefore the correct answer is option c.   3

need points to ask question

step-by-step explanation: