Question 7
Algebraically solve for x:

-3x+3+12= x6-12

3x+15=6x−12

2 Add
3
x
3x to both sides.
1
5
=
6
x
−
1
2
+
3
x
15=6x−12+3x

3 Simplify
6
x
−
1
2
+
3
x
6x−12+3x to
9
x
−
1
2
9x−12.
1
5
=
9
x
−
1
2
15=9x−12

4 Add
1
2
12 to both sides.
1
5
+
1
2
=
9
x
15+12=9x

5 Simplify
1
5
+
1
2
15+12 to
2
7
27.
2
7
=
9
x
27=9x

6 Divide both sides by
9
9.
2
7
9
=
x
9

27
=x

7 Simplify
2
7
9
9

27
to
3
3.
3
=
x
3=x

8 Switch sides.
x
=
3
x=3

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