The electric cooperative needs to know the mean household usage of electricity by its non-commercial customers in kWh per day. Assume that the population standard deviation is 2.52.5 kWh. The mean electricity usage per family was found to be 1616 kWh per day for a sample of 33943394 families. Construct the 98%98% confidence interval for the mean usage of electricity. Round your answers to one decimal place.

(15.9,16.1) is the required 98% confidence interval for mean usage of electricity.

Step-by-step explanation:

We are given the following in the question:

Sample mean, = 16 kWh

Sample size, n = 3394

Alpha, α = 0.02

Population standard deviation, σ = 2.5 kWh

98% Confidence interval:

Putting the values, we get,

(15.9,16.1) is the required 98% confidence interval for mean usage of electricity.

(3x-8) or (3x+8)

step-by-step explanation:

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-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x