How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confidence that the sample mean is within $2 of the population mean, and the population standard deviation is known to be $60.

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - α)% confidence interval for population mean (μ) is:

The margin of error of a (1 - α)% confidence interval for population mean (μ) is:

The information provided is:

σ = $60

MOE = $2

The critical value of z for 95% confidence level is:

Compute the sample size as follows:

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation: