If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t− 16t2. Find the average velocity for the time period begining when t = 2 and lasting.
a. 0.1 s.
b. 0.01 s.
c. 0.001 s.

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by .

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

what is all that apply?