Which of the following are point-slope equations of the line going through (3,
6) and (1, 2)? Check all that apply.
O A. y-2 = 4(x+1)
O B. y-6 = (x+3)
O C. y-6 = (x-3)
O D. y-6 = 4(x-3)
O E. y+2 = 4(x - 1)
O F. y-2 = (x-1)

Answer!

y=2x is the equation of the line joining (3,6)&(1,2)

and none of em satisfies the equation,none of em apply!

*explanation below*

you can check by solving equation of the options!

Step-by-step explanation:

point slope equation of (3,6) and (1,2) will be

y-2 = {(6-2)/(3-1)} (x-1)

i.e, y-2=2(x-1)

i.e, y-2=2x-2

y=2x

***using the formulae of point slope form

which is y-y1= {y2-y1/x2-x1} (x-x1)

(x1,y1)&(x2,y2) respresnts the two points given!!***

✌️:)

now simplify the option in simplest form to check which of em becomes x=2y!

a) y-2=4x+1

i.e, y=4x+3 , it's not the option

b)y-6=x+3

i.e, y=x-9 , it's not the correct option

c)y-6=x-3

i.e, y=x+3, it's not the correct option

d)y-6=4x-12

i.e, y=4x-6 ,it's not the correct option

e)y+2=4x-1

i.e, y=4x-3

f)y-2=x-1

i.e, y=x+1

none of em becames y=2x, so all of em doesn't satisfy the equation! :)✌️

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.