On a coordinate plane, a line goes through (negative 1, 1) and (0, negative 3). A point is at (negative 4, negative 3) and (0, negative 3).
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4, −3)?

y + 3 = −4(x + 4)
y + 3 = –One-fourth(x + 4)
y + 3 = One-fourth(x + 4)
y + 3 = 4(x + 4)

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step-by-step explanation:

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step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0