Provide an exact evaluation of the expression: tan(7pi/12)
a. -2(1-√3)^-2
b. 2(1+√3)^-2
c. -2(1+√3)^-2
d. 2(1-√3)^-2

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

a

step-by-step explanation:

its wrong