A 51 foot piece of wire is cut into 3 sections so that the first section is three times as long as the second section and the second is four times as long as the third. What is the length(in fett)of the longest section

The length of the longest section x = 36 ft

Step-by-step explanation:

Total length of the wire = 51 ft

Let first section of wire = x

Second section of wire = y

Third section of wire = z

According to given data

x = 3 y & y = 4 z

Total length of the wire = x + y + z = 51

y = 12

x = 3 × 12 = 36

Therefore the length of the longest section x = 36 ft

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

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