In a certain Algebra 2 class of 28 students, 23 of them play basketball and 12 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

~2.6667%

Step-by-step explanation:

idk if it's right

                 | Yes | No | t |      

Basketball   23     5   28

Baseball       12     16  28

t                    35     21   56

56/21

2.66666666666666666666666666666666666666666666666666666666 (you get it)

10/28

Step-by-step explanation:

got it right on deltamath

fsfd

step-by-step explanation:

fdddff

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.