Which point is the vertex of the quadratic function f(x)=(x-4)^2+3 a (3, 4) b (3, -4) c (-4, 3) d (4, 3)

D

Step-by-step explanation:

To find the x coordinate of the vertex, we look at the quadratic given (which is conveniently already in vertex form). We see that there is a term. The inside (x - 4) indicates where the x coordinate is. Since it is x - 4 and not x + 4, we know that the x coordinate will be positive 4 (because things are a little backward for x).

To find the y coordinate of the vertex, we look at the + 3 term at the end. The number here will indicate what the y coordinate is. Since it is + 3, and not - 3, we know that the y coordinate will be positive 3 (because things are NOT backward for y).

Thus, the vertex is D, (4, 3).

Hope this helps!

d (4,3)

Step-by-step explanation:

f(x) = (x - 4)² + 3

Vertex: (4,3)

entering that problem on the tube might get you an answer

∠cbe and ∠deb are same-side interior angles.

i took the test