What is the standard form of g(x) = (-x-4)(x-3)

g(x) = - x² - x + 12

Step-by-step explanation:

Given

g(x) = (- x - 4)(x - 3)

Each term in the second factor is multiplied by each term in the first factor, that is

- x(x - 3) - 4(x - 3) ← distribute both parenthesis

= - x² + 3x - 4x + 12 ← collect like terms

= - x² - x + 12 ← in standard form

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4