The position of a particle on the x-axis at time t, t > 0, is s(t) = ln(t) with t measured in seconds and s(t) measured in feet. what is the average velocity of the particle for e ≤ t ≤ 2e? a. ln2 b. the quotient of 1 and the quantity of 3 times c. the quotient of the natural logarithm of 2 and e d. the quotient of the natural logarithm of 2 and 2

Option: C is the correct answer.

C. the quotient of the natural logarithm of 2 and e .

Step-by-step explanation:

We are given a function s(t) that denotes the the position of a particle on the x-axis at time t, t > 0, as:

Now we are asked to find the average velocity of the particle for e ≤ t ≤ 2e.

We know that the average velocity is defined as the ratio of total distance to total time.

Now total distance covered in e ≤ t ≤ 2e is:

( Since, )

Also, total time is:

Hence, average velocity is:

Option: C is the correct answer.

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

it should be a.

hope it