"Given the coefficient values of a, b, and c, create a quadratic function g(x) in standard form. a=1, b=4, c= 3" Please Urgent I need help. If you can, also please answer this: b) Find the zeros of the function you created.
c) Find the y-intercept of the function you created. But I can find it myself

g(x) = + 4x + 3; x = -3, -1; g(x) = 3

Step-by-step explanation:

a) The standard form of a quadratic function is:

f(x) = a + bx + c

Now, replace the variables with the values given.

g(x) = + 4x + 3

b) To find the zeros of the function (x-intercepts), set y to 0 and solve for x:

g(x) = + 4x + 3

0 = + 4x + 3

(x + 3)(x + 1) = 0

(x + 3) = 0

x = -3

(x + 1) = 0

x = -1

c) To find the y-intercept of the function, set the x values to 0:

g(x) = + 4x + 3

g(x) = 3

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

the answer is  

a.

4,624π mm2

step-by-step explanation: