You are going to use an incline plane to lift a heavy object to the top of a shelving unit with a height of 5ft. The base of the incline plane is 7ft from the shelving unit. What is the length of the incline plane?

The length of the inclined plane AC = x = 8.6 ft

Step-by-step explanation:

Height = AB = 5 ft

BC = 7 ft

Now length of inclined plane AC = x

Apply pythagores theorem for ΔABC

x = 8.6 ft

Therefore the length of the inclined plane AC = x = 8.6 ft

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb