Given: ∆ABC Prove: A midsegment of ∆ABC is parallel to a side of ∆ABC.

What is the missing step in this proof?

what the heck is this   i am in the 2 grade my g and i is verrr smert

step-by-step explanation:

option c is correct.

step-by-step explanation:

the rule regarding the sides of triangle is:

(length of longest side)^2 = square of sum of other two sides.

the sides given are:

6, 10 and 8.

applying the rule we will get:

(10)^2 = (6)^2 + (8)^2

100 = 36+64

100 = 100

so, her answer is incorrect.

no, she should have added 6^2 and 8^2 and compared that to 10^2.

so, option c is correct.