A club began with 3 members. Each month, each member brought one new member. Which function can be used to determine the number of members x months after the club began

Step-by-step explanation:

The initial members in the club = 3

⇒ a   =   3

Also, let us assume the needed function is denoted by C(x).

Now, each member brings one new member in the club in 1 month.

So,  the number of members in club after 1 month

= Initial members + Addition of members

=  3 +  3  =  6

or ,

Now, at the starting of second month, initial members = 6

Each member brings 1 new member.

So, the number of new members at the end of second month = 6

Total members at the end of second month = 6+  6 = 12

Continuing the same way, we can see that:

The number of members in club after x months is:

Hence, the needed function is  :

its d. the first coordintaes are 10,32

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?