The field inside a running track is made up of rectangles that is 84.39 meters long and 73 M wide together with a half circle and east side what is the distance around the inside of the track explain or show your reasons

The field inside a running track is made up of a rectangle 84.39 m long and 73 m wide, together with a half circle at each end. The running lanes are 9.76 wide all the way around. What is the area of the running track that goes around the field? Show your work.

Area of the running track is 4187.87 m^2

Step-by-step explanation:

Given:

Inner rectangle:

Length of the rectangle = 84.39 m

Width of the rectangle = 73 m

Radius of the inner semicircle = 36.5 m

Outer rectangle:

Length of the rectangle = (73+9.76+9.76) = 92.52 m

Width of the rectangle = 84.39 m

Radius of the outer semicircle = 46.26 m

We have to find the area of the running track.

Note:

Two semicircles with same radius makes a circle.

Area of the running track = ar (outer track) - ar (inner track)

Area of the track consist of one rectangle area along with 2 semicircles area  (or a circles area).

⇒ Area of the running track :

⇒ ar (outer track) - ar (inner track)

⇒

⇒

⇒

⇒

⇒

The area of the running track that goes around the field is 4187.87 m^2

goog may have it for you

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."