URGENT!!
In the figure below, ΔABC ≅ ΔDEF. Point C is the point of intersection between segment AG and segment BF, while point E is the point of intersection between segment DG and segment BF.

The figure shows a polygon comprised of three triangles, ABC, CEG, and DFE.

Prove ΔABC ∼ ΔGEC. (10 points)

Good morning ☕️

Step-by-step explanation:

NOTE: The idea here is this:

If two pairs of corresponding angles in ΔABC and  ΔGEC are congruent, then

ΔABC ∼ ΔGEC.

since ΔABC ≅ ΔDEF then ∠ABC and ∠DEF are congruent (1)

and since the pair of angles ∠DEF and ∠CEG is vertical then ∠DEF and

∠CEG are congruent (2)

from the relations (1) and (2) we conclude that ∠ABC and ∠CEG are congruent  (3)

now, the pair of angles ∠ACB and ∠ECG is vertical then ∠ACB and

∠ECG are congruent (4)

NOTE + (3) + (4) prove that ΔABC is similar to  ΔGEC

:)

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.