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Given: ABCD is a parallelogram.
Prove: ZA 2C and ZBZD
By the definition of a , AD // BC and AB / DC.
Using, AD as a transversal, ZA and 2 are same-
side interior angles, so they are
Using side as a transversal, ZB and ZC are
same-side interior angles, so they are supplementary.
Using AB as a transversal, ZA and ZB are same-side
interior angles, so they are supplementary.
Therefore, ZA is congruent to 2C because they are
supplements of the same angle. Similarly, ZB is
congruent to
Done
1) Intro

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

step-by-step explanation:

i'm pretty sure it would take 20 hours because it's half the men so you multiply the number of hours it takes by 2

$119.20

step-by-step explanation:

$372.50 - 60% off is $149. $149-20% off is $119.20

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west