Sin(β – 10) = Cos(5β + 70)
and method pls

in steps

Step-by-step explanation:

*The question did not specify what units are β, 10 and 70 (degree or radians)

based on sin A = cos (π/2 - A)

Sin(β – 10) = cos ( π/2 - (β – 10)) = Cos(5β + 70)

(1) π/2 - (β – 10) = 5β + 70     or     (2) π/2 - (β – 10) = - (5β + 70)

if (1): π/2 - β + 10 = 5β + 70

       6β = π/2 - 60

        β = π/12 - 10    (answer depends the unit is degree or rads)

                                (π = 180°, 1 radian = 180°/π)

if (1): π/2 - β + 10 = - 5β - 70

       4β = - π/2 - 80

        β = - π/8 - 20    (answer depends the unit is degree or rads)

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

m∠a is 90°

m∠b is 40°