Solve the problem.
3) At a track meet with 135 participants, 25 participate in jumping events, of these jumpers are female, and
of the total participants are female. What is the probability that a participant chosen at random is a jumper,
given that the person is a female?

1/9 is the probability that a participant chosen at random is a jumper,  given that the person is a female.

Step-by-step explanation:

In the question, some of the data are missing.

So the correct question is "At a track meet with 135 participants, 25 participate in jumping events, 1/5 of these jumpers are female, and  1/3 of the total participants are female. What is the probability that a participant chosen at random is a jumper,  given that the person is a female?"

Given,

The number of females in the track = 1/3 of the total participants

⇒ 1/3 (135)

⇒ 45 female participants.

The number of females in jumping event = 1/5 of the jumpers

⇒ 1/5 (25)

⇒ 5 female jumpers.

To find the probability of a female jumper participant :

P(a female jumper) = No.of female jumpers / Total female participants.

⇒ 5 / 45

⇒ 1 / 9.

∴ 1/9 is the probability that a participant chosen at random is a jumper,  given that the person is a female.

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you