In a right △ABC, CD (D ∈ AB) is the angle bisector of the right ∠C. Two segments, DF (F ∈ AC) and DE (E ∈BC) are drawn parallel to the legs of the triangle. Prove that DFCE is a square.
m∠CED = 180° − m∠= by reason
m∠CFD = 180° − m∠= by reason

m∠CED = 180° − m∠ ECF = 90° by reason Same Side Interior Angles

m∠CFD = 180° −  m∠ ECF = 90° by reason Same Side Interior Angles

Step-by-step explanation:

You an see that they gave you parallel lines in DFCE. You can use these to input parallel line contingencies. You can then prove, using Same Side Interior  Angles, that angle CED and angle CFD are 90 degrees, making the shape a square as well. Hope this helped :)

sum= when you add is how much the whole amount is

distance= when you use angles and it means how far it goes

step-by-step explanation:

1) c 2143.6 cm

2) c 113.0 m

3) a 33.5 ft

4)   d 2 cm

5) c 20 mm

6) 180 in

7) d 120 ft