I don’t remember how I get the answer to this. I have the answer key though. Please help, I have a test in an hour

  f(x) = (x -2)(x -1+3i)(x -1-3i)

Step-by-step explanation:

You can use synthetic division to find the remaining quadratic factor in the cubic. Then any of the usual means of solving the quadratic will help you find its linear factors.

In the attached, I show the synthetic division, the factoring to real numbers, and the solution that finds the complex linear factors by completing the square.

Of course, you know that for zeros a, b, and c, the linear factors are ...

  f(x) = (x -a)(x -b)(x -c)

Here, we have a=2, b=1-3i, c=1+3i.

  f(x) = (x -2)(x -1+3i)(x -1-3i)

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.