What Volume of Soil, in cubic feet , does Trevor need?

Trevor only has enough soul to fill the flower box 1 foot from the top. How much soil, in cubic feet, does he have?

(a) The volume of the soil required is 48 ft³

(b) Trevor has 36 ft³ of soil

Explanation:

The trevor is made up of 2 cuboids

Dimensions of cuboid 1 = 6 ft , 3 ft and 2 ft

Dimensions of cuboid 2 = 2ft, 3 ft, 2 ft

(a)

Volume of cuboid 1 = 6 X 3 X 2 ft³

                                = 36 ft³

Volume of cuboid 2 = 2 X 3 X 2 ft³

                                 = 12 ft³

Total volume = 36 + 12 ft³

                      = 48 ft³

Therefore, the volume of the soil required is 48 ft³

(b)

If Trevor just have soil that could fill box 1, then the volume of soil is 36 ft³

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: