The probability that Shruti succeeds at any given free-throw is 80%. She was curious how many free-throws she can expect to succeed in a sample of 12 Free-throws. She simulated 25 samples of 12 free-throws where each free-throw had a 0.8 probability of being a success. Shruti counted how many free-throws were successes in each simulated sample. Here are her results:

Explanation:

The probabiity that she succeds at 10 or more free-throws in a sample of 12 free-throws is estimated from  the simulation with 25 samples of 12 free-throws:

           number of times she succeded at 10 or more free-throws      

                                         number of trials

The number of times she succeded at 10 or more free-throws is equal to the sum of the number of times she suceeded at 10 + number of times she suceeded at 11 + number of times she suceeded and 12 free-throws.

That is:

The number of trials is 25.

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation:

the answer is 21%.