(1) In 2015, the population of a small town was 8,000. The population is
increasing at a rate of 1.8% per year. Rewrite an exponential growth
function to find the monthly growth rate.

Using an exponential function, it is found that the monthly increase rate of 0.15% and the exponential function for the population after t months is given by:

In which:

In this problem:

Hence, considering the monthly increase rate of 0.15%, the exponential function for the population after t months is given by:

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Step-by-step explanation:

y= a*b x  (a is initial value  b = growth rate) y= 8000(-1)^1 x= 1.018^1 x 1.8

x = 0.1527 = time x 12.

f(x)=x. f ( x ) = x .  = 0.1527 x 12

or we can square so that x^2 = 1.8  and x = 1.34164 note this can only be used for the first 5 decimal place.

This shows the exponential growth we expand and introduce y = 8000(-1)^12 to find one year.

One year y-1^12 this represents 144 the 1.8% of the y = 144 the starting point of 1/12 on axis.

f(x)=2x. f ( x ) = 2x add y (1)^1 would show year 2 at the same rate,

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

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