What is the slope of a trend line that passes through the points (5, 80) and (7, 65)?
Negative StartFraction 15 Over 2 EndFraction
Negative StartFraction 2 Over 15 EndFraction
StartFraction 2 Over 15 EndFraction
StartFraction 15 Over 2 EndFraction

-15/2 or -7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

Step-by-step explanation:

Slope or gradient of a line is the ratio of change in y co-ordinates to the change in x co-ordinates.

Therefore;

M=∆y÷∆x

The change in y co-ordinates is given by

∆y=y2-y1

Similarly, change in x co-ordinates is given by

∆x=x2-x1

Given the two points as (5, 80) and (7, 65)

X1=5 Y1=80

X2=7 Y2=65

∆y=65-80=-15

∆x=7-5=2

Hence ∆y÷∆x will be -15÷2=-7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

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step-by-step explanation:

"exterior angles = 360 / number of sides.

60 = 360 / sides

sides = 360 / 60

sides = 6"