Write an equation for a line that passes through the Irgun and perpendicular to y=5x-2

Well we have to find eq of line passing through origin and perpendicular to y=5x-2

First you need slope

As slope of y=5x-2 line is 5

So, slope of perpendicular line is -1/5

Also it passes through origin

as we know eq of line is y-y1=m(x-x1)

substitute X1,y1 = (0,0)

it becomes y =mx

so, y = -x/5

5y +x = 0 is required equation

i dont know

step-by-step explanation:

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)