One root of the equation x^2+6x+q=0 is twice the other root. Find q and the roots.

q = 8

x₁ = -2, x₂ = -4

Step-by-step explanation:

For a quadratic equation ax² + bx + c, the sum of the roots is -b/a, and the product of the roots is c/a.

If the roots are x₁ and x₂, then:

-6/1 = x₁ + x₂

q/1 = x₁ x₂

Since we know one root is double the other, we can say x₂ = 2x₁.  Plugging into the first equation and solving:

-6 = x₁ + 2x₁

-6 = 3x₁

x₁ = -2

Which means x₂ = -4.  So the value of q must be:

q/1 = (-2) (-4)

q = 8

answer: a

step-by-step explanation:

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above