20 POINTS!

If the two equations are graphed, at what point do the lines representing the two equations intersect?

y = -1/2x + 1
y = 1/4x + 4

(6, -2)
(-4, 3)
(4, -1)
(-2, 2)

(-4, 3)

Step-by-step explanation:

y = -1/2x + 1

This has a y intercept of 1 and a slope of -1/2

Graph a point at x=0 y=1 and go down 1 to the right 2

draw a line from the first point

y = 1/4x + 4

This has a y intercept of 4 and a slope of 1/4

Graph a point at x=0 y=4 and go up 1 to the right 4

draw a line from the first point

as you can see in the graph, the lines intersect at -4,3

(-4,3)

Step-by-step explanation:

y = -1/2x + 1

y = 1/4x + 4

¼x = y - 4

y = -2(¼x) + 1

y = -2(y - 4) + 1

y = -2y + 8 + 1

3y = 9

y = 3

¼x = 3 - 4

¼x = -1

x = -4

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²