John's average for making free throws in a basketball game is .80. in a one-and-one free throw situation (where he shoots a second basket only if he makes the first), what is the probability that he makes exactly one basket?

0.16

Step-by-step explanation:

Given that John's average for making free throws in a basketball game is .80.

He can get a chance for II throw only if he hits the first

So required probability = Prob that he hits the first but misses the second

Prob for hitting a single trial = 0.8 which is constant for each throw

Prob for missing a single trial = 1-0.8 = 0.2 since there are only two outcomes

Hence required probability = 0.8(1-0.2) = 0.16

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00