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6 Math HONORS (K) QTR 4 (SY2019-20) UPDATED
Bus Stop:
O
Distance (miles
Recall that Seth's house is 17 miles
from school. Which location should
Seth start off at to get to school
faster and how long will it take?
6
12
Time (minute
Friend's
House:
Time (min)
Distance (mi)
000
from the bus stop is faster, taking
17 minutes
from the bus stop is faster, taking
24 minutes
from his friend's house is faster,
takin
15 minute
Intro
Done

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

c. 6tan80

step-by-step explanation:

the answer would be 0.54

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.