Moises is rolling a number cube, with sides numbered 1 through 6, 30 times. How many times should he expect to roll an odd number?

15 times

Step-by-step explanation:

To find the expected count you have to multiply the probability of the favorable event with the number of repetitions/rolls.  For a fair dice, every number will have the same probability to occur. The dice have number 1 to 6 which mean there are 3 odd numbers (2, 4, 6) out of 6 possible number.

Then the probability for odd number will be: 3/6= 1/2  

The expected count of odd numbers in 30 rolls will be= 1/2 * 30 =15 times.

i dont know

step-by-step explanation:

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.