Given y=-3/4x-2. What is the equation of the line that is perpendicular and has the point (-4,1)? Write answer in slope intercept form.

y=4/3+19/3

Step-by-step explanation:

When it asks for perpendicular it means your focusing on the slope.

Perpendicular means opposite of the current slope, so flip it and change the sign (-3/4 changes to 4/3). Next you will use the equation (y-y1)=m(x-x1)

y1=the y value given

x1=the x value given

m=your slope

(y-1)=4/3(x+4)     Since the x point is minus a negative we get to change the sign to a positive. Next distribute the 4/3 to each term in the parenthesis.

y-1=4/3(x)+4/3(4)

y-1=4/3x+16/3     Now we add the one to both sides.

 +1          +1          The one isn't in teh correct format to just add so first imagine it as 1/1. Now to get the bottom to have a 3 like in 16/3 we just multiply the top and bottom by 3.

      Now we can add this to the 16/3

 We can now put this back into our equation.

y=4/3+19/3

∠cbe and ∠deb are same-side interior angles.

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