How large a sample must be drawn so that a 99.5% confidence interval for µ will have a margin of error equal to 1.1? Round up the answer to the nearest integer. (Round the critical value to no less than three decimal places.) A sample size of is needed to be drawn in order to obtain a 99.5% confidence interval with a margin of error equal to 1.1.

A sample size of 2018 is needed to be drawn in order to obtain a 99.5% confidence interval with a margin of error equal to 1.1.

Step-by-step explanation:

Missing data:

The value of population standard deviation is 17.6

We have been provided with the following data:

Confidence Level = 99.5%

Margin of error = M.E = 1.1

Population standard Deviation = = 17.6

What we have to do is find the minimum sample size required to keep the margin of error upto 1.1 with 99.5% confidence level.

Since, the value of population standard deviation is known, we will use the formulas of z-distribution to solve the question.

Formula of Margin of Error is:

Here,

is the z critical value for the given confidence level. From the z-table the z-value for 99.5% confidence level comes out to be 2.807

Using the values in above formula, we get:

Rounding up to the nearest integer, the minimum sample size required is 2018.

A sample size of 2018 is needed to be drawn in order to obtain a 99.5% confidence interval with a margin of error equal to 1.1.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.