−4x+60<72 OR 14x+11<−31minus, 4, x, plus, 60, is less than, 72, start color #ed5fa6, start text, space, O, R, space, end text, end color #ed5fa6, 14, x, plus, 11, is less than, minus, 31
Choose 1
Choose 1

(Choice A)
A
x<-3x<−3x, is less than, minus, 3 or x>-3x>−3x, is greater than, minus, 3

(Choice B)
B
x>-3x>−3x, is greater than, minus, 3

(Choice C)
C
x<-3x<−3x, is less than, minus, 3

(Choice D)
D
There are no solutions

(Choice E)
E
All values of xxx are solutions

boxplot e is the answer

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: