Can the law of sines be used to solve the triangle
shown? Explain.
40
45°
30

Step-by-step explanation:

If BD_|_AC

in trg BDA ,sin 45=BD/40=V2/2

BD*2=40V2

BD=40V2/2=20V2  and AD=BD

so CD=30-AD=30-20V2

in trg BCD,  BC^2=BD^2+CD^2

                     BC^2=(20V2)^2+(30-20V2)^2=

                     (20V2)^2+30^2-2*30*20V2+(20V2)^2=

                     400*2+900-1200V2+400*2=

                     800+900-1200V2+800=

                      2700-1200V2

so  BC=V100(27-12V2)=10V(27-12V2

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step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

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