Is (x-2) a factor of (x3-8x2+14x-4)?

The value of the polynomial function st x = 2 is zero hence x - 2 is a factor of  x³-8x²+14x-4.

Given the polynomial function x³-8x²+14x-4. In order to check if x - 2 is a factor, we must show that P(2) = 0

P(x) = x³-8x²+14x-4.

r(x) =x - 2

If r(x) = 0

x - 2 = 0

x = 2

Substitute x = 2 into the polynomail function

P(2) = 2³-8(2)²+14(2)-4

P(2) = 8 - 32 + 28 - 4

P(2) = -24 + 24

P(2) = 0

Since the value of the polynomial function st x = 2 is zero hence x - 2 is a factor of  x³-8x²+14x-4.

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Definitely/Yes.

Factor it yourself and you get x-2.

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b