JK is tangent to a circle with centre H as shown below. What is HK ?
8 mi
15 mi

Given:

JK is tangent to a circle with center H

To find:

The length of HK.

Solution:

The image is attached below.

JK = 8 mi, HJ = 15 mi

JK is tangent to a circle.

The tangent is always perpendicular to the radius.

Therefore, m∠J = 90°

Using Pythagoras theorem:

HK² = JK² + HJ²

HK² = 8² + 15²

HK² = 64 + 225

HK² = 289

HK² = 17²

Taking square root on both sides.

HK = 17

The length of HK is 17 mi.

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is