Since the 3-Dimensional Matching Problem is NP- complete, it is natural to expect that the corresponding 4-Dimensional Matching Problem is at least as hard. Let us define 4-Dimensional Matching as follows. Given sets W , X , Y , and Z , each of size n, and a collection C of ordered 4-tuples of the form (wi, xj, yk, zl), do there exist n 4-tuples from C so that no two have an element in common? Prove that 4-Dimensional Matching is NP-Complete.

i think it would be 43 movies that would have to be watched.

step-by-step explanation:

think about it. for the second plan, every month is 8 dollars. 8 x 12= 96. so thats the number for the second plan. now for the first plan, its annual meaning you have to pay 10 dollars every year. so now you have to get an equivalent amount of 86 since 96-10=86. 86 divided by 2 since every movie costs 2$ then you would have to watch 43 movies a year to get the same as the second plan. i really hoped this . have a wonderful day as well!

e.

step-by-step explanation:

because there are always 10 numbers in a phone number.

x + 4/7

step-by-step explanation:

use cymath